ExoSynkLab

Your first circuit: blink an LED

Public·Apr 19, 2026·1

Your first circuit: blink an LED

A 9V battery, a resistor, and an LED. Why the resistor matters, how to read current, and how to fix it when the LED goes dark.

Your first circuit: blink an LED

Welcome to ExoSynk. This is the classic "hello world" of electronics — and it's three components.

What you need

  • 9V battery — the source
  • 330Ω resistor — the current limiter
  • LED — the output

That's it. The companion lab is @exosynk/blink.

Why the resistor?

An LED is not a regular bulb. It has a forward voltage (usually around 2V for red LEDs) — below that voltage it's off, above it the current rises fast, and above its max current (~20 mA for standard through-hole LEDs) it burns out.

Connecting a 9V battery straight to an LED would push something like 1 amp through it. It would glow for about 0.2 seconds, then go dark forever.

The resistor "eats" the extra voltage. Ohm's law:

I = (V_battery − V_led) / R
I = (9V − 2V) / 330Ω
I = 21 mA

Right in the happy range. LED glows brightly, nothing burns.

Try it

  1. Open @exosynk/blink
  2. Click Fork in the top-right — now it's your lab
  3. Change the battery to 3V. Does the LED still light? (It might not — 3V − 2V = 1V across a 330Ω resistor is only 3 mA, which is barely visible.)
  4. Change the resistor to 100Ω with the 9V battery. Watch the LED go orange, then 💥 BURNT — we've exceeded max current.

What you learned

  • LEDs need current-limiting resistors.
  • Ohm's law picks the resistor value.
  • In ExoSynk the simulation is honest — burn-outs are real.

Next up: voltage dividers.

E

The Virtual Electronics Lab. Design circuits in your browser, wire them up, run real physics — then (later) order your build as actual hardware.

See @exosynk's profile →

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